Ace the Java Fsoft Academy Challenge 2026 – Code Your Way to Success!

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What will happen when you compile and run the following Java code? abstract class Base { abstract void amethod(); static int i; } public class Derived extends Base { public static void main(String[] argv) { int[] ar = new int[5]; for (i = 0; i < ar.length; i++) System.out.print(ar[i]); } }

The program compiles but prints nothing.

The program fails to compile because the subclass does not implement an abstract method.

Abstract methods require concrete subclasses to provide implementations. In this code, the base class has an abstract method amethod, so any non-abstract subclass must implement amethod. The Derived class shown does not implement that method and is not declared abstract, so the code fails to compile. If you added an implementation for amethod in Derived, the program would compile and run; it would print five zeros because the int array elements are initialized to 0 by default and you print each element in the loop.

The program prints 00000.

The program throws a runtime exception.